x2-x1-20=x2-3x

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Solution for x2-x1-20=x2-3x equation: 



x2-x1-20=x2-3x

We move all terms to the left:

x2-x1-20-(x2-3x)=0

We add all the numbers together, and all the variables

-(+x^2-3x)+x2-x1-20=0

We add all the numbers together, and all the variables

x^2-(+x^2-3x)-1x-20=0

We get rid of parentheses

x^2-x^2+3x-1x-20=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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