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x2-9x-4.75=0
We add all the numbers together, and all the variables
x^2-9x-4.75=0
a = 1; b = -9; c = -4.75;
Δ = b2-4ac
Δ = -92-4·1·(-4.75)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-10}{2*1}=\frac{-1}{2} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+10}{2*1}=\frac{19}{2} =9+1/2 $
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