x2-7x-368=0

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Solution for x2-7x-368=0 equation:



x2-7x-368=0
We add all the numbers together, and all the variables
x^2-7x-368=0
a = 1; b = -7; c = -368;
Δ = b2-4ac
Δ = -72-4·1·(-368)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-39}{2*1}=\frac{-32}{2} =-16 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+39}{2*1}=\frac{46}{2} =23 $

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