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x2-75x+625=0
We add all the numbers together, and all the variables
x^2-75x+625=0
a = 1; b = -75; c = +625;
Δ = b2-4ac
Δ = -752-4·1·625
Δ = 3125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3125}=\sqrt{625*5}=\sqrt{625}*\sqrt{5}=25\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-25\sqrt{5}}{2*1}=\frac{75-25\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+25\sqrt{5}}{2*1}=\frac{75+25\sqrt{5}}{2} $
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