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x2-60x+32=0
We add all the numbers together, and all the variables
x^2-60x+32=0
a = 1; b = -60; c = +32;
Δ = b2-4ac
Δ = -602-4·1·32
Δ = 3472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3472}=\sqrt{16*217}=\sqrt{16}*\sqrt{217}=4\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{217}}{2*1}=\frac{60-4\sqrt{217}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{217}}{2*1}=\frac{60+4\sqrt{217}}{2} $
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