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x2-4x=5x-18
We move all terms to the left:
x2-4x-(5x-18)=0
We add all the numbers together, and all the variables
x^2-4x-(5x-18)=0
We get rid of parentheses
x^2-4x-5x+18=0
We add all the numbers together, and all the variables
x^2-9x+18=0
a = 1; b = -9; c = +18;
Δ = b2-4ac
Δ = -92-4·1·18
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3}{2*1}=\frac{12}{2} =6 $
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