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x2-4x+10=6.
We move all terms to the left:
x2-4x+10-(6.)=0
We add all the numbers together, and all the variables
x2-4x+10-6=0
We add all the numbers together, and all the variables
x^2-4x+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{4}{2}=2$
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