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x2-40x+60=0
We add all the numbers together, and all the variables
x^2-40x+60=0
a = 1; b = -40; c = +60;
Δ = b2-4ac
Δ = -402-4·1·60
Δ = 1360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1360}=\sqrt{16*85}=\sqrt{16}*\sqrt{85}=4\sqrt{85}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-4\sqrt{85}}{2*1}=\frac{40-4\sqrt{85}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+4\sqrt{85}}{2*1}=\frac{40+4\sqrt{85}}{2} $
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