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x2-3x-10(x2-5x-6)=144
We move all terms to the left:
x2-3x-10(x2-5x-6)-(144)=0
We add all the numbers together, and all the variables
-10(+x^2-5x-6)+x2-3x-144=0
We add all the numbers together, and all the variables
x^2-10(+x^2-5x-6)-3x-144=0
We multiply parentheses
x^2-10x^2+50x-3x+60-144=0
We add all the numbers together, and all the variables
-9x^2+47x-84=0
a = -9; b = 47; c = -84;
Δ = b2-4ac
Δ = 472-4·(-9)·(-84)
Δ = -815
Delta is less than zero, so there is no solution for the equation
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