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x2-3.9x+3.5=0
We add all the numbers together, and all the variables
x^2-3.9x+3.5=0
a = 1; b = -3.9; c = +3.5;
Δ = b2-4ac
Δ = -3.92-4·1·3.5
Δ = 1.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.9)-\sqrt{1.21}}{2*1}=\frac{3.9-\sqrt{1.21}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.9)+\sqrt{1.21}}{2*1}=\frac{3.9+\sqrt{1.21}}{2} $
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