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x2-2x=146
We move all terms to the left:
x2-2x-(146)=0
We add all the numbers together, and all the variables
x^2-2x-146=0
a = 1; b = -2; c = -146;
Δ = b2-4ac
Δ = -22-4·1·(-146)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14\sqrt{3}}{2*1}=\frac{2-14\sqrt{3}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14\sqrt{3}}{2*1}=\frac{2+14\sqrt{3}}{2} $
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