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x2-2x-39600=0
We add all the numbers together, and all the variables
x^2-2x-39600=0
a = 1; b = -2; c = -39600;
Δ = b2-4ac
Δ = -22-4·1·(-39600)
Δ = 158404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{158404}=398$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-398}{2*1}=\frac{-396}{2} =-198 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+398}{2*1}=\frac{400}{2} =200 $
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