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x2-26x-128=0
We add all the numbers together, and all the variables
x^2-26x-128=0
a = 1; b = -26; c = -128;
Δ = b2-4ac
Δ = -262-4·1·(-128)
Δ = 1188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1188}=\sqrt{36*33}=\sqrt{36}*\sqrt{33}=6\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-6\sqrt{33}}{2*1}=\frac{26-6\sqrt{33}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+6\sqrt{33}}{2*1}=\frac{26+6\sqrt{33}}{2} $
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