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x2-25x-2500=0
We add all the numbers together, and all the variables
x^2-25x-2500=0
a = 1; b = -25; c = -2500;
Δ = b2-4ac
Δ = -252-4·1·(-2500)
Δ = 10625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10625}=\sqrt{625*17}=\sqrt{625}*\sqrt{17}=25\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25\sqrt{17}}{2*1}=\frac{25-25\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25\sqrt{17}}{2*1}=\frac{25+25\sqrt{17}}{2} $
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