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x2-25x+36=0
We add all the numbers together, and all the variables
x^2-25x+36=0
a = 1; b = -25; c = +36;
Δ = b2-4ac
Δ = -252-4·1·36
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{481}}{2*1}=\frac{25-\sqrt{481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{481}}{2*1}=\frac{25+\sqrt{481}}{2} $
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