x2-25x+24=0

Solution for x2-25x+24=0 equation:

x2-25x+24=0

We add all the numbers together, and all the variables

x^2-25x+24=0

a = 1; b = -25; c = +24;
Δ = b2-4ac
Δ = -252-4·1·24
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-23}{2*1}=\frac{2}{2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+23}{2*1}=\frac{48}{2}
=24
$