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x2-2001x+9350=0
We add all the numbers together, and all the variables
x^2-2001x+9350=0
a = 1; b = -2001; c = +9350;
Δ = b2-4ac
Δ = -20012-4·1·9350
Δ = 3966601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2001)-\sqrt{3966601}}{2*1}=\frac{2001-\sqrt{3966601}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2001)+\sqrt{3966601}}{2*1}=\frac{2001+\sqrt{3966601}}{2} $
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