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x2-2.4x=2.2
We move all terms to the left:
x2-2.4x-(2.2)=0
We add all the numbers together, and all the variables
x^2-2.4x-2.2=0
a = 1; b = -2.4; c = -2.2;
Δ = b2-4ac
Δ = -2.42-4·1·(-2.2)
Δ = 14.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{14.56}}{2*1}=\frac{2.4-\sqrt{14.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{14.56}}{2*1}=\frac{2.4+\sqrt{14.56}}{2} $
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