# x2-15x=225

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## Solution for x2-15x=225 equation:

x2-15x=225
We move all terms to the left:
x2-15x-(225)=0
We add all the numbers together, and all the variables
x^2-15x-225=0
a = 1; b = -15; c = -225;Δ = b2-4acΔ = -152-4·1·(-225)Δ = 1125The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$The end solution:
$\sqrt{\Delta}=\sqrt{1125}=\sqrt{225*5}=\sqrt{225}*\sqrt{5}=15\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15\sqrt{5}}{2*1}=\frac{15-15\sqrt{5}}{2}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15\sqrt{5}}{2*1}=\frac{15+15\sqrt{5}}{2}$

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