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x2-15x=225

We move all terms to the left:

x2-15x-(225)=0

We add all the numbers together, and all the variables

x^2-15x-225=0

a = 1; b = -15; c = -225;

Δ = b^{2}-4ac

Δ = -15^{2}-4·1·(-225)

Δ = 1125

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1125}=\sqrt{225*5}=\sqrt{225}*\sqrt{5}=15\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15\sqrt{5}}{2*1}=\frac{15-15\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15\sqrt{5}}{2*1}=\frac{15+15\sqrt{5}}{2} $

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