x2-13x+42=(x-7)(x+6)

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Solution for x2-13x+42=(x-7)(x+6) equation: 



x2-13x+42=(x-7)(x+6)

We move all terms to the left:

x2-13x+42-((x-7)(x+6))=0

We add all the numbers together, and all the variables

x^2-13x-((x-7)(x+6))+42=0

We multiply parentheses ..

x^2-((+x^2+6x-7x-42))-13x+42=0



We calculate terms in parentheses: -((+x^2+6x-7x-42)), so:

(+x^2+6x-7x-42)

We get rid of parentheses

x^2+6x-7x-42

We add all the numbers together, and all the variables

x^2-1x-42

Back to the equation:

-(x^2-1x-42)



We add all the numbers together, and all the variables

x^2-13x-(x^2-1x-42)+42=0

We get rid of parentheses

x^2-x^2-13x+1x+42+42=0

We add all the numbers together, and all the variables

-12x+84=0

We move all terms containing x to the left, all other terms to the right

-12x=-84

x=-84/-12

x=+7

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