x2-104x+400=0

Solution for x2-104x+400=0 equation:

x2-104x+400=0

We add all the numbers together, and all the variables

x^2-104x+400=0

a = 1; b = -104; c = +400;
Δ = b2-4ac
Δ = -1042-4·1·400
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-96}{2*1}=\frac{8}{2}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+96}{2*1}=\frac{200}{2}
=100
$