x2-(x+1)(x+2)/5x+1=6

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Solution for x2-(x+1)(x+2)/5x+1=6 equation: 



x2-(x+1)(x+2)/5x+1=6

We move all terms to the left:

x2-(x+1)(x+2)/5x+1-(6)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

x^2-(x+1)(x+2)/5x-5=0

We multiply parentheses ..

x^2-(+x^2+2x+x+2)/5x-5=0

We multiply all the terms by the denominator


-(+x^2+2x+x+2)+x^2*5x-5*5x=0

Wy multiply elements

-(+x^2+2x+x+2)+5x^3-25x=0

We get rid of parentheses

-x^2+5x^3-2x-x-25x-2=0

We do not support expression: x^3

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