x2+x/3=10

Solution for x2+x/3=10 equation:

x2+x/3=10

We move all terms to the left:

x2+x/3-(10)=0

We add all the numbers together, and all the variables

x^2+x/3-10=0

We multiply all the terms by the denominator


x^2*3+x-10*3=0

We add all the numbers together, and all the variables

x^2*3+x-30=0

Wy multiply elements

3x^2+x-30=0

a = 3; b = 1; c = -30;
Δ = b2-4ac
Δ = 12-4·3·(-30)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*3}=\frac{-20}{6}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*3}=\frac{18}{6}
=3
$