x2+x-20=104

Solution for x2+x-20=104 equation:

x2+x-20=104

We move all terms to the left:

x2+x-20-(104)=0

We add all the numbers together, and all the variables

x^2+x-124=0

a = 1; b = 1; c = -124;
Δ = b2-4ac
Δ = 12-4·1·(-124)
Δ = 497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{497}}{2*1}=\frac{-1-\sqrt{497}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{497}}{2*1}=\frac{-1+\sqrt{497}}{2}
$