x2+x+2x+200=4000

Solution for x2+x+2x+200=4000 equation:

x2+x+2x+200=4000

We move all terms to the left:

x2+x+2x+200-(4000)=0

We add all the numbers together, and all the variables

x^2+3x-3800=0

a = 1; b = 3; c = -3800;
Δ = b2-4ac
Δ = 32-4·1·(-3800)
Δ = 15209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{15209}}{2*1}=\frac{-3-\sqrt{15209}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{15209}}{2*1}=\frac{-3+\sqrt{15209}}{2}
$