x2+9x-252=0

Solution for x2+9x-252=0 equation:

x2+9x-252=0

We add all the numbers together, and all the variables

x^2+9x-252=0

a = 1; b = 9; c = -252;
Δ = b2-4ac
Δ = 92-4·1·(-252)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-33}{2*1}=\frac{-42}{2}
=-21
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+33}{2*1}=\frac{24}{2}
=12
$