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x2+8x-1584=0
We add all the numbers together, and all the variables
x^2+8x-1584=0
a = 1; b = 8; c = -1584;
Δ = b2-4ac
Δ = 82-4·1·(-1584)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-80}{2*1}=\frac{-88}{2} =-44 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+80}{2*1}=\frac{72}{2} =36 $
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