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x2+7x-68.75=0
We add all the numbers together, and all the variables
x^2+7x-68.75=0
a = 1; b = 7; c = -68.75;
Δ = b2-4ac
Δ = 72-4·1·(-68.75)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-18}{2*1}=\frac{-25}{2} =-12+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+18}{2*1}=\frac{11}{2} =5+1/2 $
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