x2+6x-53=0

Solution for x2+6x-53=0 equation:

x2+6x-53=0

We add all the numbers together, and all the variables

x^2+6x-53=0

a = 1; b = 6; c = -53;
Δ = b2-4ac
Δ = 62-4·1·(-53)
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{62}}{2*1}=\frac{-6-2\sqrt{62}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{62}}{2*1}=\frac{-6+2\sqrt{62}}{2}
$