x2+6x-504=0

Solution for x2+6x-504=0 equation:

x2+6x-504=0

We add all the numbers together, and all the variables

x^2+6x-504=0

a = 1; b = 6; c = -504;
Δ = b2-4ac
Δ = 62-4·1·(-504)
Δ = 2052
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2052}=\sqrt{36*57}=\sqrt{36}*\sqrt{57}=6\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{57}}{2*1}=\frac{-6-6\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{57}}{2*1}=\frac{-6+6\sqrt{57}}{2}
$