x2+6x+8=4+10x

Solution for x2+6x+8=4+10x equation:

x2+6x+8=4+10x

We move all terms to the left:

x2+6x+8-(4+10x)=0

We add all the numbers together, and all the variables

x2+6x-(10x+4)+8=0

We add all the numbers together, and all the variables

x^2+6x-(10x+4)+8=0

We get rid of parentheses

x^2+6x-10x-4+8=0

We add all the numbers together, and all the variables

x^2-4x+4=0

a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{2}=2$