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x2+6x+27=-5x+3
We move all terms to the left:
x2+6x+27-(-5x+3)=0
We add all the numbers together, and all the variables
x^2+6x-(-5x+3)+27=0
We get rid of parentheses
x^2+6x+5x-3+27=0
We add all the numbers together, and all the variables
x^2+11x+24=0
a = 1; b = 11; c = +24;
Δ = b2-4ac
Δ = 112-4·1·24
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*1}=\frac{-16}{2} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*1}=\frac{-6}{2} =-3 $
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