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x2+5x-2250=0
We add all the numbers together, and all the variables
x^2+5x-2250=0
a = 1; b = 5; c = -2250;
Δ = b2-4ac
Δ = 52-4·1·(-2250)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-95}{2*1}=\frac{-100}{2} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+95}{2*1}=\frac{90}{2} =45 $
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