x2+3x=550

Solution for x2+3x=550 equation:

x2+3x=550

We move all terms to the left:

x2+3x-(550)=0

We add all the numbers together, and all the variables

x^2+3x-550=0

a = 1; b = 3; c = -550;
Δ = b2-4ac
Δ = 32-4·1·(-550)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-47}{2*1}=\frac{-50}{2}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+47}{2*1}=\frac{44}{2}
=22
$