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x2+3x+15=3
We move all terms to the left:
x2+3x+15-(3)=0
We add all the numbers together, and all the variables
x^2+3x+12=0
a = 1; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·1·12
Δ = -39
Delta is less than zero, so there is no solution for the equation
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