x2+36x+35=0

Solution for x2+36x+35=0 equation:

x2+36x+35=0

We add all the numbers together, and all the variables

x^2+36x+35=0

a = 1; b = 36; c = +35;
Δ = b2-4ac
Δ = 362-4·1·35
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-34}{2*1}=\frac{-70}{2}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+34}{2*1}=\frac{-2}{2}
=-1
$