x2+34x+145=0

Solution for x2+34x+145=0 equation:

x2+34x+145=0

We add all the numbers together, and all the variables

x^2+34x+145=0

a = 1; b = 34; c = +145;
Δ = b2-4ac
Δ = 342-4·1·145
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-24}{2*1}=\frac{-58}{2}
=-29
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+24}{2*1}=\frac{-10}{2}
=-5
$