x2+32=2x2-12

Solution for x2+32=2x2-12 equation:

x2+32=2x^2-12

We move all terms to the left:

x2+32-(2x^2-12)=0

We add all the numbers together, and all the variables

x^2-(2x^2-12)+32=0

We get rid of parentheses

x^2-2x^2+12+32=0

We add all the numbers together, and all the variables

-1x^2+44=0

a = -1; b = 0; c = +44;
Δ = b2-4ac
Δ = 02-4·(-1)·44
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*-1}=\frac{0-4\sqrt{11}}{-2}
=-\frac{4\sqrt{11}}{-2}
=-\frac{2\sqrt{11}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*-1}=\frac{0+4\sqrt{11}}{-2}
=\frac{4\sqrt{11}}{-2}
=\frac{2\sqrt{11}}{-1}
$