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x2+31x+234=0
We add all the numbers together, and all the variables
x^2+31x+234=0
a = 1; b = 31; c = +234;
Δ = b2-4ac
Δ = 312-4·1·234
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-5}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+5}{2*1}=\frac{-26}{2} =-13 $
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