x2+2x-3/4=0

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Solution for x2+2x-3/4=0 equation:



x2+2x-3/4=0
We add all the numbers together, and all the variables
x^2+2x-3/4=0
We multiply all the terms by the denominator
x^2*4+2x*4-3=0
Wy multiply elements
4x^2+8x-3=0
a = 4; b = 8; c = -3;
Δ = b2-4ac
Δ = 82-4·4·(-3)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{7}}{2*4}=\frac{-8-4\sqrt{7}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{7}}{2*4}=\frac{-8+4\sqrt{7}}{8} $

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