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x2+2x+2=145
We move all terms to the left:
x2+2x+2-(145)=0
We add all the numbers together, and all the variables
x^2+2x-143=0
a = 1; b = 2; c = -143;
Δ = b2-4ac
Δ = 22-4·1·(-143)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-24}{2*1}=\frac{-26}{2} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+24}{2*1}=\frac{22}{2} =11 $
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