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x2+29x+120=0.
We add all the numbers together, and all the variables
x^2+29x+120=0
a = 1; b = 29; c = +120;
Δ = b2-4ac
Δ = 292-4·1·120
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-19}{2*1}=\frac{-48}{2} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+19}{2*1}=\frac{-10}{2} =-5 $
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