x2+26x+133=0

Solution for x2+26x+133=0 equation:

x2+26x+133=0

We add all the numbers together, and all the variables

x^2+26x+133=0

a = 1; b = 26; c = +133;
Δ = b2-4ac
Δ = 262-4·1·133
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-12}{2*1}=\frac{-38}{2}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+12}{2*1}=\frac{-14}{2}
=-7
$