x2+21x+54=0

Solution for x2+21x+54=0 equation:

x2+21x+54=0

We add all the numbers together, and all the variables

x^2+21x+54=0

a = 1; b = 21; c = +54;
Δ = b2-4ac
Δ = 212-4·1·54
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-15}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+15}{2*1}=\frac{-6}{2}
=-3
$