If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2+2019x+1=0
We add all the numbers together, and all the variables
x^2+2019x+1=0
a = 1; b = 2019; c = +1;
Δ = b2-4ac
Δ = 20192-4·1·1
Δ = 4076357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2019)-\sqrt{4076357}}{2*1}=\frac{-2019-\sqrt{4076357}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2019)+\sqrt{4076357}}{2*1}=\frac{-2019+\sqrt{4076357}}{2} $
| 21x+12=14x-28 | | 3+4=5-t | | 2x+6=8x-8 | | x-23=-25 | | 5v-4/10=66 | | 4x-15x+18=100 | | 2/x=−12 | | 3(x-3)+3(4x-1)=0 | | 5y-13=-y+5+2y | | $112=x-$16 | | $112=$16x | | 0.4=x/15 | | 4(x+7)-15=72 | | 7*n=0 | | -4=-6x+x-4 | | -3v2+8v-1=-4v2-1 | | 5g+4(-5+3g)=1+ | | 2x+10-4x-4x=18 | | |2x+5|=|x+3-4x+2| | | x+x+(2x–5)=23x+x+(2x+5)=23 | | -4x2-2x-24=-5x2 | | r-(5-r)=13+2r | | 2X+-200=5x+100 | | 4(x+1)-3(x+1)-3(x-5)=17(x-5)=17 | | 13x+20=9x+30+2 | | 3x-6=4+10x | | 3x-4+26=180 | | p-36=18 | | (10=7r-r^) | | 2y-14y+15=12 | | B-6=k-6 | | X+3/16=1/8+x-5/5 |