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x2+200x=166400
We move all terms to the left:
x2+200x-(166400)=0
We add all the numbers together, and all the variables
x^2+200x-166400=0
a = 1; b = 200; c = -166400;
Δ = b2-4ac
Δ = 2002-4·1·(-166400)
Δ = 705600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{705600}=840$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-840}{2*1}=\frac{-1040}{2} =-520 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+840}{2*1}=\frac{640}{2} =320 $
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