x2+2-(-2x)=x-2-(x2-1)

Solution for x2+2-(-2x)=x-2-(x2-1) equation:

x2+2-(-2x)=x-2-(x2-1)

We move all terms to the left:

x2+2-(-2x)-(x-2-(x2-1))=0

We add all the numbers together, and all the variables

-(x-2-(+x^2-1))+x2-(-2x)+2=0

We add all the numbers together, and all the variables

x^2-(x-2-(+x^2-1))-(-2x)+2=0

We get rid of parentheses

x^2-(x-2-(+x^2-1))+2x+2=0


We calculate terms in parentheses: -(x-2-(+x^2-1)), so:

x-2-(+x^2-1)

determiningTheFunctionDomain
-(+x^2-1)+x-2

We get rid of parentheses

-x^2+x+1-2

We add all the numbers together, and all the variables

-1x^2+x-1

Back to the equation:

-(-1x^2+x-1)


We get rid of parentheses

x^2+1x^2-x+2x+1+2=0

We add all the numbers together, and all the variables

2x^2+x+3=0

a = 2; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·2·3
Δ = -23
Delta is less than zero, so there is no solution for the equation