x2+19x+70=0

Solution for x2+19x+70=0 equation:

x2+19x+70=0

We add all the numbers together, and all the variables

x^2+19x+70=0

a = 1; b = 19; c = +70;
Δ = b2-4ac
Δ = 192-4·1·70
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-9}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+9}{2*1}=\frac{-10}{2}
=-5
$