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x2+13x-2704=0
We add all the numbers together, and all the variables
x^2+13x-2704=0
a = 1; b = 13; c = -2704;
Δ = b2-4ac
Δ = 132-4·1·(-2704)
Δ = 10985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10985}=\sqrt{169*65}=\sqrt{169}*\sqrt{65}=13\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13\sqrt{65}}{2*1}=\frac{-13-13\sqrt{65}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13\sqrt{65}}{2*1}=\frac{-13+13\sqrt{65}}{2} $
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