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x2+12x+26=0
We add all the numbers together, and all the variables
x^2+12x+26=0
a = 1; b = 12; c = +26;
Δ = b2-4ac
Δ = 122-4·1·26
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{10}}{2*1}=\frac{-12-2\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{10}}{2*1}=\frac{-12+2\sqrt{10}}{2} $
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